49x^2+12=56x

Solution for 49x^2+12=56x equation:

49x^2+12=56x

We move all terms to the left:

49x^2+12-(56x)=0

a = 49; b = -56; c = +12;
Δ = b2-4ac
Δ = -562-4·49·12
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-28}{2*49}=\frac{28}{98}
=2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+28}{2*49}=\frac{84}{98}
=6/7
$